0=t^2-12t+36

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Solution for 0=t^2-12t+36 equation: 



0=t^2-12t+36

We move all terms to the left:

0-(t^2-12t+36)=0

We add all the numbers together, and all the variables

-(t^2-12t+36)=0

We get rid of parentheses

-t^2+12t-36=0

We add all the numbers together, and all the variables

-1t^2+12t-36=0

a = -1; b = 12; c = -36;
Δ = b2-4ac
Δ = 122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-12}{-2}=+6$

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